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A slingshot fires a pebble from the top of a building at a speed of 17.5 m/s. The building is 31.5 m tall. Ignoring air resistance, find the speed with which the pebble strikes the ground when the pebble is fired in the following directions.

Respuesta :

princessesther2011

Answer:

The speed with which the pebble strikes the ground is 30.4m/s

Explanation:

Initial velocity (u) = 17.5m/s, height (h) = 31.5m, acceleration due to gravity (g) = 9.8m/s^2

V^2 = u^2 + 2gh = 17.5^2 + 2×9.8×31.5 = 306.25 + 617.4 = 923.65

V^2 = 923.65

V = √923.65 = 30.4m/s

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