When barium chloride reacts with potassium sulfate, barium sulfate and potassium chloride arc produced. The balanced equation for this reaction is: BaCl2(aq) + K2SO4(aq) → BaSO4(s) + 2KCl(aq) If 2 moles of potassium sulfate react, The reaction consumes _moles of barium chloride. The reaction produces moles of barium sulfate and ____moles of potassium chloride.

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anfabba15 anfabba15 · Answer 1 · 2020-01-17T02:47:59+01:00

Answer:

Ratio between the reactants is 1:1, so if 2 moles of potassium sulfate react, The reaction consumes 2 moles of barium chloride

The reaction produces 2 moles of barium sulfate ( ratio is 1:1) and 4 moles of potassium chloride. (Ratio with this is 2:4)

Explanation:

This is the reaction:

BaCl₂(aq) + K₂SO₄(aq) → BaSO₄(s) + 2KCl(aq)

Ratio between the reactants is 1:1, so if 2 moles of potassium sulfate react, The reaction consumes 2 moles of barium chloride

The reaction produces 2 moles of barium sulfate ( ratio is 1:1) and 4 moles of potassium chloride. (Ratio with this is 2:4)

thomasdecabooter thomasdecabooter · Answer 2 · 2020-01-17T04:59:27+01:00

Answer:

The reaction consumes 2.0 moles of barium chloride. The reaction produces 2.0 moles of barium sulfate and 4.0 moles of potassium chloride.

Explanation:

Step 1: Data given

2 moles of potassium sulfate react

Step 2: The balanced equation

BaCl2(aq) + K2SO4(aq) → BaSO4(s) + 2KCl(aq)

Step 3: Calculate moles

For 1 mol BaCl2 we need 1 mol K2SO4 to produce 1 mol Ba2SO4 and 2 moles KCl

For 2 moles K2SO4 we need 2 moles BaCl2 to produce 2 moles BaSO4 and 4 moles KCl

The reaction consumes 2.0 moles of barium chloride. The reaction produces 2.0 moles of barium sulfate and 4.0 moles of potassium chloride.