Answer:
The required force is calculated as 79.69 N
Solution:
As per the question:
Angle, [tex]\theta = 5^{\circ}[/tex]
Force, F = 40 N
The angle after the ball is being pulled, [tex]\theta' = 10^{\circ}[/tex]
Now,
To calculate the required force:
The tension in the string can be calculated by considering the vertical component:
[tex]F = Tsin\theta[/tex]
where
T = Tension in the cord
Now,
[tex]T = \frac{F}{sin\theta} = \frac{40}{sin5^{\circ}} = 458.94\ N[/tex]
Now, after the cord is being pulled, the force exerted is given by:
[tex]F' = Tsin\theta' = 458.94\times sin10^{\circ} = 79.69\ N[/tex]
