Answer:
There are produced 1,65 mol of nitrous oxide gas.
Explanation:
The reaction of nitrogen gas and oxygen gas to produce nitrous oxide gas is:
2 N₂(g) + O₂(g) → 2 N₂O(g)
This balanced reaction is saying that per 2 moles of nitrogen gas in excess of oxygen there are produced 2 moles of nitrous oxide gas. That means that per 1,65 moles of nitrogen gas there are produced:
1,65 mol N₂(g) ×[tex]\frac{2 mol N_{2}O}{2 mol N_{2}}[/tex] = 1,65 mol N₂O
I hope it helps!