The television show Degenerate Housewives has been successful for many years. That show recently had a share of 18, meaning that among the TV sets in use, 18% were tuned to Degenerate Housewives. Assume that an advertiser wants to verify that 18% share value by conducting its own survey, and a pilot survey begins with 12 households have TV sets in use at the time of a Degenerate Housewivesbroadcast.Find the probability that none of the households are tuned to Degenerate Housewives. P(none) = Find the probability that at least one household is tuned to Degenerate Housewives. P(at least one) = Find the probability that at most one household is tuned to Degenerate Housewives. P(at most one) = _If at most one household is tuned to Degenerate Housewives, does it appear that the 18% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Degenerate Housewives unusual?)

Given that the television show Degenerate Housewives has been successful for many years. That show recently had a share of 18, meaning that among the TV sets in use, 18% were tuned to Degenerate Housewives.

Each household is independent of the other and there two outcomes.

X no of households that are tuned to Degenerate Housewives. is Bin (12, 0.18)

the probability that none of the households are tuned to Degenerate Housewives. P(none) =_______0.0924_____

the probability that at least one household is tuned to Degenerate Housewives. P(at least one) = ____1-0.0924 = 0.9076______

the probability that at most one household is tuned to Degenerate Housewives. P(at most one) = _____0.3359______

If at most one household is tuned to Degenerate Housewives, does it appear that the 18% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Degenerate Housewives unusual?)

No 33% is not unusual.