Answer:
gs = 0.6 m/s^2
Explanation:
Given data:
velocity = 12 m/s
height s = 12t -(1/2) g_s t^2
Given velocity is the derivatives of height
[tex]v(t) = \frac{d}{dt} s(t)[/tex]
[tex]= \frac{d}{dt}(12t -\frac{1}{2} g_s t^2)[/tex]
[tex]= 12 - g_s t[/tex]
when velocity tend to 0 , maximum height is reached
[tex]v(t) = 12 - g_s t[/tex]
[tex]0 = 12 - g_s t[/tex]
[tex]g_s = \frac{12}{t}[/tex]
at t = 20 sec ball reached the max height, so
[tex]g_s = \frac{12}{20} = 0.6 m/s^2[/tex]
