Respuesta :
Answer:
[tex]F_{piston} = 600 N[/tex]
Explanation:
[tex]F_{car}[/tex] = weight of the car = Force on the larger piston = 15000 N
[tex]r_{1}[/tex] = radius of the larger piston = 0.20 m
[tex]F_{piston}[/tex] = force on the smaller piston
[tex]r_{2}[/tex] = radius of the smaller piston = 0.040 m
Using pascal's law, Pressure must be equal on each piston, hence
[tex]\frac{F_{car}}{\pi r_{1}^{2} } = \frac{F_{piston}}{\pi r_{2}^{2} } \\\\\frac{15000}{0.20^{2} } = \frac{F_{piston}}{0.040^{2} }\\\\F_{piston} = 600 N[/tex]
600 N force must be applied to this smaller piston in order to lift the car.
Let's solve the question:
Pascal's Law:
It states that if some pressure is applied at any point of incompressible liquid then the same pressure is transmitted to all the points of liquid and on the walls of the container.
Given:
Force on car, F= 15,000 N
Radius of larger piston, r₁ = 0.20m
Radius of larger piston, r₂ = 0.040m
To find:
Force on piston, F=?
Using Pascal's law:
[tex]\frac{F_{car}}{\pi r_1^2} =\frac{F_{piston}}{\pir_2^2}\\\\ \frac{15000}{0.20^2}=\frac{F_{piston}}{0.40^2}\\\\F_{piston}=600N[/tex]
600 N force must be applied to this smaller piston in order to lift the car.
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