Answer:
[tex]32\text{ for }x=0.\overline{40}[/tex]
Step-by-step explanation:
It looks like you want the sum of digits of the product ...
[tex]x = (0.\overline{6})(0.\overline{60})=\dfrac{2}{3}\cdot\dfrac{20}{33}=\dfrac{40}{99}=0.\overline{40}[/tex]
Since the decimal fraction starts off with 4 and has an even number of repeating digits, there will be 8 4's and 7 0's in the sum of the first 15 decimal digits:
sum = 8×4 +7×0 = 32
The sum of the first 15 digits after the decimal point is 32.
