The magnetic field of an electromagnetic wave in a vacuum is Bz =(2.4μT)sin((1.05×107)x−ωt), where x is in m and t is in s. You may want to review (Pages 889 - 892) . For help with math skills, you may want to review: Rearrangement of Equations Involving Multiplication and Division Part A What is the wave's wavelength? Express your answer to three significant figures and include the appropriate units.

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Answer:

Explanation:

Given

[tex]B_z=(2.4\mu T)\sin (1.05\times 10^7x-\omega t)[/tex]

Em wave is in the form of

[tex]B=B_0\sin (kx-\omega t)[/tex]

where [tex]\omega =frequency\ of\ oscillation[/tex]

[tex]k=wave\ constant[/tex]

[tex]B_0=Maximum\ value\ of\ Magnetic\ Field[/tex]

Wave constant for EM wave k is

[tex]k=1.05\times 10^7 m^{-1}[/tex]

Wavelength of wave [tex]\lambda =\frac{2\pi }{k}[/tex]

[tex]\lambda =\frac{2\pi }{1.05\times 10^7}[/tex]

[tex]\lambda =5.98\times 10^{-7} m[/tex]

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