Answer:
Power = 606.83 hp/mile
Explanation:
Given data:
diameter of pipeline is 36 inches = 3ft
flow rate is 590,000 barrels per day = 28.755 ft^3/sec
temperature of pipe = 46 degree celcius
length of pipe is 1.9 mile = 10032 ft
velocity of flow[tex] = \frac{28.755}{\frac{\pi}{4} 3^2} = 4.068 ft/s[/tex]
applying bernouli eq at two point in pipeline
P1 = P2
v1 = v2
z1 = z2 so we have
[tex]h_{in} = h_f[/tex]
[tex]h_{in} = \frac{ flv^2}{2gD}[/tex]
[tex]h_{in} = \frac{0.0155 \times 10032 \times 4.068^2}{2\times 32.174 \times 3}[/tex]
[tex]h_{in} = 13.32 ft[/tex]
POwer [tex]P = \rho gQ h_{in}[/tex]
[tex]P = 53.71 \times 32.174 \times 27.755 \times 13.32 = 634141.29 ldf ft/sec[/tex]
Power P = 1152.99 hp 0
power needed for each mile [tex]= \frac{1152.99}{1.9} = 606.83 hp/mile[/tex]
