Answer:
2.12*10^-4 moles
Explanation:
If 3.03ml contains 1.35*10^-4mol then 7.79 will contain 7.79ml*1.35*10^-4/3.03= 3.47*10^-4 moles
Amount added= (3.47-1.35)*10^-4=2.12*10^-4moles
Answer: 2.12 X 10^-4
Explanation:
First, find the final number of moles of radon in the container after the addition by rearranging Avogadro's law to solve for n2.
n2= V2 × n1 / V1
Substitute the known values ofn1, V1, and V2.
n2 = 7.79 mL × 1.35 × 10^−4 mol / 3.03 mL = 3.47 × 10^−4 mol
Find the difference between the final number of moles (n2) and the initial number of moles (n1).
n2−n1 = 3.47 × 10^-4 mol −1 .35 × 10^−4 mol= 2.12 × 10^−4mol