Answer:
The answer to your question is below
Step-by-step explanation:
The shape is an irregular quadrilateral shape.
Perimeter
1.- Find the length of the four sides
dAB = [tex]\sqrt{(-5 + 25)^{2} + (-32 + 11)^{2} }[/tex]
= [tex]\sqrt{20^{2} + 21^{2} }[/tex]
= [tex]\sqrt{841}[/tex]
= 29 u
dAD = [tex]\sqrt{(-4 + 25)^{2} + (9 + 11)^{2} }[/tex]
= [tex]\sqrt{21^{2} + 20^{2} }[/tex]
= [tex]\sqrt{441 + 400}[/tex]
= [tex]\sqrt{841}[/tex]
= 29 units
dBC = [tex]\sqrt{(37 + 5)^{2} + (8 + 32)^{2} }[/tex]
= [tex]\sqrt{42^{2} + 40^{2} }[/tex]
= [tex]\sqrt{1764 + 1600}[/tex]
= [tex]\sqrt{3364}[/tex]
= 58 units
dCD = [tex]\sqrt{(-4 - 37)^{2} + (9 -8)^{2} }[/tex]
= [tex]\sqrt{-41^{2} + 1x^{2} }[/tex]
= [tex]\sqrt{1681 + 1}[/tex]
= [tex]\sqrt{1682}[/tex]
= 41.01 units
Perimeter = 29 + 29 + 58 + 41.01 = 157.01 ≈ 157 units
Area
To find the area divide the figure in a square and a triangle
Area of the square = 29 x 29 = 841 units²
Area of the triangle = (base x height) / 2
base = 58 - 29 = 29
height = 29
= ( 29 x 29) / 2
= 841 / 2
= 420.5 units²
Total area = 841 + 420-5 = 1261.5 units²
