Answer:
The items were on Johnny's list was 5 and Bobby's 13.
Step-by-step explanation:
Given:
Bobby's christmas list had 3 more times as many items on it than Johnny's list.
Johnny asked for 8 fewer items than bobby.
Now, to find the number of items were on Johnny's and Bobby's christmas list.
Let the number of items on Johnny's list be [tex]x[/tex].
And let the number of items on Bobby's list be [tex]y[/tex].
So, as given in question:
Bobby's christmas list had 3 more times as many items on it than Johnny's list:
[tex]y=3+2x.[/tex].......( 1 )
And, Johnny asked for 8 fewer items than bobby:
[tex]y-8=x.[/tex]
Now, putting the value of [tex]y[/tex] from equation ( 1 ) in the place of [tex]y[/tex] :
⇒ [tex]3+2x-8=x[/tex]
⇒ [tex]2x-5=x[/tex]
Adding 5 on both sides we get:
⇒ [tex]2x=x+5[/tex]
Subtracting [tex]x[/tex] on both sides we get:
⇒ [tex]x=5.[/tex]
Thus, Johnny's list = 5 items.
Now, putting the value of [tex]x[/tex] in equation ( 1 ) we get:
[tex]y=3+2(5)[/tex]
⇒ [tex]y=3+2\times 5[/tex]
⇒ [tex]y=3+10[/tex]
⇒ [tex]y=13.[/tex]
Hence, Bobby's list = 13 items.
Therefore, the items were on Johnny's list was 5 and Bobby's 13.
