Answer:
Test statistic z= 1.708
Step-by-step explanation:
given that a television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If this is to happen, it will have to move one of its most viewed shows to another slot.
Sample size n = 827
Sample proportion p = [tex]\frac{438}{827} \\=0.5297[/tex]
[tex]H_0: p =0.5\\H_a: p >0.5[/tex]
(right tailed test)
This is because they would be interested if more than half viewers are ready for the change
Test statistic = Z = p difference/std error
p difference = 0.0297
Std error =[tex]\sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.5*0.5}{827} } \\=0.0174[/tex]
Z =1.708
p valu e= 0.9562
Since p >0.05 we fail to reject H0
Test statistic z= 1.708
