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A ten-loop coil having an area of 0.23 m^2 and a very large resistance is in a 0.047-T uniform magnetic field oriented so that the maximum flux goes through the coil. The coil is then rotated so that the flux through it goes to zero in 0.34 s. What is the magnitude of the average emf induced in the coil during the 0.34 s?

a. 1.0 nV
b. 3.2 nV
c. 0.0 nV
d. 0.32 nV

Respuesta :

cjmejiab

To solve this problem it is necessary to consider the definition of the electromotive force or induced compass emf as

[tex]emf = N \frac{d\phi}{dt}[/tex]

Where,

N = Number of Loops

t = Time

[tex]\phi =[/tex] Electric Field also defined as

[tex]\phi =[/tex]BA

B= Magnetic field

A = Cross sectional Area

Replacing our values we have that,

[tex]emf =10*\frac{(0.047*0.23)}{0.34}[/tex]

[tex]emf = 0.3179nV \approx 0.32nV[/tex]

Therefore the correct answer is D.

onyebuchinnaji

The average emf induced in the coil for the given time is 0.32 V.

The given parameters;

  • area of the loop, A = 0.23 m²
  • magnitude of the magnetic field, B = 0.047 T
  • change in time of the coil, t = 0.34 s
  • number of turns, N = 10

The average emf induced in the coil for the given time is calculated using Faradays law;

[tex]emf = N\frac{d\phi}{dt} \\\\emf = N \times \frac{BA}{t} \\\\emf = 10 \times \frac{0.23 \times 0.047}{0.34} \\\\emf = 0.32 \ V[/tex]

Thus, the average emf induced in the coil for the given time is 0.32 V.

Learn more here:https://brainly.com/question/12974419

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