Answer:
Fc₂ = 4.675 N
Explanation:
r₁ = 12 cm = 0.12 m
Fc= 1.7 N
Fc = mV²/r = m w² r ( ∴ V= r w )
Fc = m w² r ----------------------- (1)
As angular speed (w) and mass are constant.
let m * w² = k ------------------(2)
Put equation (2) in equation (1).
⇒ Fc = m w² r = k * r ( ∴ m w² = k)
⇒ Fc =k * r ----------------------( 3)
⇒ Fc₁ =k * r₁ = 1.7 N
⇒ k = 1.7/ r = 1.7 / 0.12 N ( as r₁=0.12 m )
⇒ k = 14.17
Centripetal force hen the rod is fixed at 33 cm from the axis:
From equation ( 3 )
Fc₂ = k * r₂
Fc₂ = 14.17 * 0.33 N ( ∴ r₂ = 0.33 m)
Fc₂ = 4.675 N
