Answer:
1422.8 m
Explanation:
Given:
Displacement of the truck is, [tex]\vec S=1430\ m[/tex]
The direction of the truck's displacement is 5.76° with the horizontal.
A vector inclined at angle [tex]\theta[/tex] with the horizontal is resolved into 2 components which are mutually perpendicular to each other. One of the component is along the horizontal and the other is along the vertical.
If a vector 'A' is inclined at an angle [tex]\theta[/tex] with the horizontal, then its horizontal and vertical components are given as:
[tex]Horizontal:\\A_x=A\cos \theta\\\\Vertical:\\A_y=A\cos \theta[/tex]
Here, the vector is 'S' and its horizontal component is needed.
Therefore, the horizontal component is given as:
[tex]S_x=S\cos \theta\\S_x=1430\times \cos(5.76\°)\\S_x=1422.8\ m[/tex]
