A journal published a study of the lifestyles of visually impaired students. Using​ diaries, the students kept track of several​ variables, including number of hours of sleep obtained in a typical day. These visually impaired students had a mean of 8.888.88 hours and a standard deviation of 2.092.09 hours. Assume that the distribution of the number of hours of sleep for this group of students is approximately normal. Complete parts a through c.a. Find P(x < 6)b. Find P(8<=x<=10)c. Find the value for which P(x

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Answer:

a) P(X < 6) = 0.0838

b) P(8<=x<=10) = 0.3682

c) a = 7.1244

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

[tex]\mu = 8.88, \sigma = 2.09[/tex]

a. Find P(x < 6)

This is the pvalue of Z when X = 6. So:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{6 - 8.88}{2.09}[/tex]

[tex]Z = -1.38[/tex]

[tex]Z = -1.38[/tex] has a pvalue of 0.0838.

So P(X < 6) = 0.0838

b. Find P(8<=x<=10)

This is the pvalue of Z when X = 10 subtracted by the pvalue of Z when X = 8. So:

X = 10

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{10 - 8.88}{2.09}[/tex]

[tex]Z = 0.54[/tex]

[tex]Z = 0.54[/tex] has a pvalue of 0.7054.

X = 8

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{8 - 8.88}{2.09}[/tex]

[tex]Z = -0.42[/tex]

[tex]Z = -0.42[/tex] has a pvalue of 0.3372.

So P(8<=x<=10) = 0.7054 - 0.3372 = 0.3682

c. Find the value for which P(x < a) = 0.2

This is X = a when Z has a pvalue of 0.2. So [tex]Z = -0.84[/tex]

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-0.84 = \frac{a - 8.88}{2.09}[/tex]

[tex]a - 8.88 = 2.09*(-0.84)[/tex]

[tex]a = 7.1244[/tex]

For the normal distribution, P(x < 6) is 8.38% while P(8<=x<=10) is 36.82%

Z score

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (x - μ)/σ

where x is raw score, σ is standard deviation and μ is mean

From the question,

μ = 8.88, σ = 2.09

For x < 6:

z = (6 - 8.88)/2.09 = -1.38

P(z < -1.38) = 0.0838

For x > 8:

z = (8 - 8.88)/2.09 = -0.42

For x < 10:

z = (10 - 8.88)/2.09 = 0.54

P(-0.42< z < 0.54) = P(z < 0.54) - P(z < -0.42) = 0.7054 - 0.3372 = 0.3682

P(x < 6) is 8.38% while P(8<=x<=10) is 36.82%

Find out more on Z score at: https://brainly.com/question/25638875

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