Answer & Explanation:
Given:
Propagation delay = [tex]32ms[/tex]
Segment size = [tex]1162bytes[/tex]
Link transmission rate = [tex]23Mbps[/tex]
Round trip time = [tex]2\times[/tex]Propagation delay = [tex]2\times32ms = 64ms[/tex]
Calculating the total segment: [tex]total\:segment = \frac{Receiver\:window \:size}{sender\:segment}=\frac{7873}{1162}=6.7753\approx 6 [/tex]
[tex]through put = \frac{segment}{Round-trip\:time}=\frac{1162byte}{64ms}=\frac{1162\times8bits}{64\times{10^{-3}}s}=145.25\times{10^{3}}bps [/tex]
[tex]utilization=\frac{throughout}{bandwidth}=\frac{145.25\times 10^{3}bps}{23Mbps}=\frac{145.25\times 10^{3}bps}{23\times 10^{6} bps}=6.315\times 10^{3-6}=6.315\times 10^{-3}=0.0063[/tex]
Utilization in percentage is 0.63%
Over all Utilization = [tex]6\times 0.63\%=3.78\%[/tex]
