Answer:
The new temperature of the water bath is 36.8°C
Explanation:
A Calorimety problem to apply this formula:
Q = m . C . ΔT
Where Q is heat
m is mass
C is specific heat capacity
ΔT = T° final - T° initial
Let's make some conversion before
97.1 kJ .1000 = 97100 Joules
3.70 kg . 1000 = 3700 g
This because the specific heat capacity units
ΔT it's a difference and mathematically, in numbers, it is the same value in °C as in K
97100 J = 3700 g . 4.18J / g°C ( T°final - 30.5°C)
97100 J = 15466 J/°C (T°final - 30.5°C)
97100 J / 15466 °C/J = (T°final - 30.5°C)
6.28°C = T °final - 30.5°C
6.28° C + 30.5°C = T°final
36.8°C = T° final
