Answer:
8
Step-by-step explanation:
The equation is
[tex] log_{3}(3x + 2) =log_{3}(4x- 6) [/tex]
Since the bases are equal, the arguments are also equal, so we obgain
[tex]3x + 2 = 4x - 6[/tex]
Grouping like terms we obtain:
[tex]2 + 6 = 4x - 3x[/tex]
[tex] \implies x = 8[/tex]
