the certain Forest covers an area of 2000 square kilometers suppose that each year this area take creases by 6% what is the equation that best represents the area of the force each year hint use the formula y equals p​

Respuesta :

Answer:

The equation which represent the area of forest creases each year is 2000 km² [tex](0.94)^{12}[/tex] and

The area is 952 km² .

Step-by-step explanation:

Given as :

The rate of depreciation of forest area each year = r = 6%

The initial area of forest = i = 2000 square kilometers

Let The final area of forest = f = x square kilometers

The time period for depreciation = 12 year

Now, According to question

The final area of forest = The initial area of forest × [tex](1-\dfrac{\textrm rate}{100})^{\textrm time}[/tex]

Or,  f =  i ×  [tex](1-\dfrac{\textrm r}{100})^{\textrm 12}[/tex]

Or,  f =  2000 km² × [tex](1-\dfrac{\textrm 6}{100})^{\textrm 12}[/tex]

Or,  f =  2000 km² × [tex](0.94)^{12}[/tex]

∴ f =  2000 km² × 0.475920

I.e f = 951.84 ≈ 952 km²

So, The equation which represent the area of forest creases each year = f = 952 km²

Hence,The equation which represent the area of forest creases each year is 2000 km² [tex](0.94)^{12}[/tex] and the area is 952 km² . Answer

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