Moe paid $223 for buying computer.
Step-by-step explanation:
Given,
Cost of computer = $1056.00
Let,
Amount contributed by Larry = x
Amount contributed by Moe = y
Amount contributed by Curly = z
According to given statement;
x+y+z=1056 Eqn 1
x=y+150 Eqn 2
y=z-237 Eqn 3
Putting value of y from Eqn 3 in Eqn 2
[tex]x=(z-237)+150\\x=z-237+150\\x=z-87\ \ \ Eqn\ 4[/tex]
Putting value of xx and y from Eqn 3 and 4 in Eqn 1
[tex](z-87)+(z-237)+z=1056\\z-87+z-237+z=1056\\3z-324=1056\\3z=1056+324\\3z=1380[/tex]
Dividing both sides by 3
[tex]\frac{3z}{3}=\frac{1380}{3}\\z=460[/tex]
Putting z=460 in Eqn 3
[tex]y=460-237\\y=223[/tex]
Moe paid $223 for buying computer.
Keywords: linear equation substitution method
Learn more about linear equations at:
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