What are the zeros of the polynomial function?

Answer:
-1
1
2
Step-by-step explanation:
x³+2x²-x-2=(x²-1)(x-2)
(x²-1)(x-2)=0
x²-1=0
x-2=0
x12=√1
----------------
x1=-1
x2=1
x3=2
x
Answer:
-2, -2, 1
Step-by-step explanation:
simply substitute each potential answer into f(x) and see which one results in f(x) = 0,
f(x) = x³ + 2x² - x - 2
f(-3) = (-3)³ + 2(-3)² - (-3) - 2 = -8(not a root)
f(-2) = (-2)³ + 2(-2)² - (-2) - 2 = 0(Is a root!)
f(-1) = (-1)³ + 2(-1)² - (-1) - 2 = 0 (Is a root!)
f(0) = (0)³ + 2(0)² - (0) - 2 = -2 (not a root)
f(1) = (1)³ + 2(1)² - (1) - 2 = 0(Is a root!)
f(2) = (2)³ + 2(2)² - (2) - 2 = 12(not a root)
f(3) = (3)³ + 2(3)² - (3) - 2 = 40(not a root)