Answer:
Probability of event = 0.28
Step-by-step explanation:
At a fundraiser, a school group charges $8 for tickets for a "grab bag".
You choose one bill at random from a bag that contains 36 $1 bills, 19 $5 bills, 6 $10 bills, 7 $20 bills, and 3 $100 bills.
The total number of bills = 36 + 19 + 6 + 7 +3 =71 bills.
We have to find the probability that i will be able to win enough to pay my ticket that is he must get at least $8.
The price would be sufficient if he gets $10, $20 or $100 bills.
So the favorable cases = 20
Total cases = 71
hence probability = [tex]\frac{20}{71}[/tex] = 0.28
The probability of him getting price greater than his ticket = 0.28
