Answer:
The equation of the line is 2 x - y = 1.
Step-by-step explanation:
Here the given points are ( 2, 3) & ( 0, -1 )
Equation of a line whose points are given such that
( [tex]x_{1}, y_{1}[/tex] ) & ( [tex]x_{2}, y_{2}[/tex] )
y - [tex]y_{1}[/tex] = [tex]\frac{ y_{2} - y_{1} }{x_{2} - x_{1} }[/tex] ( x - [tex]x_{1}[/tex] )
i.e. y - 3 = [tex]\frac{-1 - 3}{ 0- 2}[/tex] ( x- 2)
y - 3 = [tex]\frac{- 4}{- 2}[/tex] ( x - 2 )
y - 3 = 2 ( x - 2 )
y - 3 = 2 x - 4
2 x - y = 4- 3
2 x - y = 1
Hence the equation of the required line whose passes trough the points ( 2, 3) & ( 0, - 1) is 2 x - y = 1.
