Answer:
1.2 M
Explanation:
Let's consider the following reversible reaction.
CuS(s) + O₂(g) ⇌ Cu(s) + SO₂(g)
To find the equilibrium concentration of O₂ we will use an ICE Chart. We will only consider gases and aqueous species since the activity of solids and liquids is 1.
CuS(s) + O₂(g) ⇌ Cu(s) + SO₂(g)
I 2.9 0
C -x +x
E 2.9-x x
The equilibrium constant (Kc) is:
[tex]Kc=1.5=\frac{[SO_{2}]}{[O_{2}]} =\frac{x}{2.9-x} \\x=1.7[/tex]
The concentration of O₂ at equilibrium is:
[O₂] = 2.9 -x = 2.9 - 1.7 = 1.2 M