Answer:
(a)spring effective force constant =1568N/cm
(b) Yes
Explanation:
Hooke's law is represented mathematically as, F=ke
where
- F is force applied to elastic material,
(a).After the maximum load is exceeded, Hooke's law doesn't apply anymore. from the problem, its stated that a maximum load of 120kg will cause an extension of 0.75cm, we will use this to determine the spring constant.
F=mg, g=9.8[tex]m/s^{2}[/tex]
F= 120*9.8 =1176N
From Hooke's law, k=[tex]\frac{F}{e}[/tex]
k=[tex]\frac{1176}{0.75}[/tex]
k=1568N/cm
(b). The players who stands on the scale causes a 0.48cm extension.
e= 0.48cm, k= 1568N/cm
F=Ke
F= 1568*0.48
F= 752.64N
To calculate the mass of the player we divide this force by g=9.8[tex]m/s^{2}[/tex]
F=mg
m=F/g
[tex]m= \frac{ 752.64}{9.8} \\\\m=76.8kg[/tex]
since the rugby team is an under 85kg team, this player with 76.8kg mass is eligible
