What does the following loop do?int[] a = {6, 1, 9, 5, 12, 3};int len = a.length;int x = 0;for (int i = 1; i < len; i++)if (a[i] > a[x]) x = i;System.out.println(x);1. Finds the position of the largest value in a.2. Sums the elements in a.3. Finds the position of the smallest value in a.4. Counts the elements in a.
Option 1: Finds the position of the largest value in a
Explanation:
Given the codes as follows:
int[] a = {6, 1, 9, 5, 12, 3};
int len = a.length;
int x = 0;
for (int i = 1; i < len; i++)
{
if (a[i] > a[x])
x = i;
}
System.out.println(x);
The code is intended to find a largest value in the array, a. The logic is as follows:
Define a variable to hold an index where largest value positioned. At the first beginning, just presume the largest value is held at index zero, x = 0. (Line 3)
Next, compare the value location in next index. If the value in the next index is larger, update the index-x to the next index value (Line 4 - 8). Please note the for-loop traverse the array starting from index 1. This is to enable the index-1 value can be compared with index-0 and then followed with index-2, index-3 etc.
After completion of the for-loop, the final x value will be the index where the largest value is positioned.
