Answer:
a) 0.26
b) 1077 MPa
Explanation:
a) The following equation can be used to determine the volume fraction:
[tex]\frac{F_f}{F_m} =\frac{E_fV_f}{E_m(1-V_f)}[/tex]
[tex]\frac{0.97}{1-0.97} =\frac{260V_f}{2.8(1-V_f)}[/tex]
[tex]32.3 = \frac{260V_f}{2.8-2.8V_f}[/tex]
[tex]V_f = 0.26[/tex]
b) Tensile strength can be found by using the following equation:
[tex]\sigma_{cl} = \sigma_m(1-V_f)+\sigma_fV_f = 50*(1-0.26)+4000*0.26 = 1077[/tex] MPa
