Answer:
17
Explanation:
Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.
[tex]X\rightarrow X^{n+}+ne^-[/tex]
Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.
[tex]X^{n+}+ne^-\rightarrow X[/tex]
For the given chemical reaction:
[tex]BrO_3^-(s)+Sb^{3+}(aq.)\rightarrow Br^-(aq.)+5Sb^{5+}(aq)[/tex]
The half cell reactions for the above reaction follows:
Reduction half reaction: [tex]BrO_3^-+6H^++6e^-\rightarrow Br^{-}+3H_2O[/tex]
Oxidation half reaction: [tex]Sb^{3+}\rightarrow Sb^{5+}+2e^-[/tex]
Multiplying the Oxidation half reaction by 3 and we get that:-
[tex]3Sb^{3+}\rightarrow 3Sb^{5+}+6e^-[/tex]
Adding the half reactions, we get that:-
[tex]BrO_3^-+6H^++3Sb^{3+}\rightarrow Br^{-}+3Sb^{5+}+3H_2O[/tex]
The sum of the coefficients is:- 1 + 6 + 3 + 1 + 3 + 3 = 17
