Answer:
0.11
Explanation:
The given equilibrium reaction and the equilibrium concentrations are shown below as:-
[tex]\begin{matrix}&N_2&+&3H_2&\rightleftharpoons &2NH_3\\Concentration\ at\ equilibrium:-&1.5&&1.1&&0.47\end{matrix}[/tex]
The Kc of an equilibrium reaction measures relative amounts of the products and the reactants present during the equilibrium.
It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.
The equation is as follows:-
[tex]N_2_{(g)} +3H_2_{(g)}\rightarrow 2NH_3_{(g)}[/tex]
The expression for the Kc is:-
[tex]K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}[/tex]
Thus, applying the values as:-
[tex]K_c=\frac{0.47^2}{1.5\times 1.1^3}=0.11[/tex]
