contestada

Consider the partially-filled array named a. What does the following loop do? (cin is a Scanner object)int[] a = {1, 3, 7, 0, 0, 0};int size = 3, capacity = 6;int value = cin.nextInt();while (value > 0){a[size] = value;size++;value = cin.nextInt();}1. May crashe at runtime because it can input more elements than the array can hold2. Reads up to 3 values and inserts them in the array in the correct position.3. Reads one value and places it in the remaining first unused space endlessly.4. Reads up to 3 values and places them in the array in the unused space.

Respuesta :

teobguan2019

Answer:

Option 1: May crash at runtime because it can input more elements than the array can hold

Explanation:

Given the code as follows:

  1.        int[] a = {1, 3, 7, 0, 0, 0};
  2.        int size = 3, capacity = 6;
  3.        int value = cin.nextInt();
  4.        while (value > 0)
  5.        {
  6.            a[size] = value;
  7.            size++;
  8.            value = cin.nextInt();
  9.        }

From the code above, we know the a is an array with six elements (Line 1). Since the array has been initialized with six elements, the capacity of the array cannot be altered in later stage.

However, a while loop is created to keep prompting for user input an integer and overwrite the value in the array started from index 3 (Line 4- 9). In every round of loop, the index is incremented by 1 (Line 7). If the user input for variable value is always above zero, the while loop will persist.  This may reach a point where the index value is out of bound and crash the program. Please note the maximum index value for the array is supposedly be 5.  

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE

Otras preguntas