Answer for the question No.17
Answer:
[tex]x=28.11\ degree[/tex]
[tex]m\angle\ ABC=28.11\ degree[/tex]
Step-by-step explanation:
Answer for the question No.17
Given:-
[tex]\angle\ BAD=(5x+10)\ degree[/tex]
[tex]\angle\ ADC=(87)\ degree[/tex]
[tex]\angle\ DCB=(3x+10)\ degree[/tex]
Let,[tex]m\angle\ ABC=x[/tex]
In quadrilateral ABCD,
[tex]\angle\ BAD+\angle\ ABC+\angle\ DCB +\angle\ ADC =360\ degree[/tex] ---(sum of angle of quadrilateral is 360 degree)
[tex]\therefore\ (5x+10)+x+(3x+10)+87=360[/tex]
[tex]9x+107=360[/tex]
[tex]9x=360-107[/tex]
[tex]9x=253[/tex]
[tex]x=\frac{253}{9}[/tex]
[tex]\therefore\ x=28.11\ degree[/tex]
SInce x=[tex]m\angle ABC[/tex]
[tex]\therefore\ m\angle\ ABC=28.11\ degree[/tex]
