Answer:
c. is more than that of the fluid.
Explanation:
This problem is based on the conservation of energy and the concept of thermal equilibrium
[tex]heat= m s \Delta T [/tex]
m= mass
s= specific heat
\DeltaT=change in temperature
let s1= specific heat of solid and s2= specific heat of liquid
then
Heat lost by solid= [tex]20(s_1)(70-30)=800s_1 [/tex]
Heat gained by fluid=[tex]100(s_2)(30-20)=1000s_2 [/tex]
Now heat gained = heat lost
therefore,
1000 S_2=800 S_1
S_1=1.25 S_2
so the specific heat of solid is more than that of the fluid.
The correct option is:
(c) is more than that of the fluid.
Conservation of energy:
The conservation of energy suggests that the heat energy lost by the solid must be equal to the heat energy gained by the liquid.
Let the specific heat of the solid be [tex]s_s[/tex] and the specific heat of the liquid be [tex]s_l[/tex].
Heat energy lost by the solid is given by:
[tex]\Delta Q_s=ms_s\Delta T\\\\ \Delta Q_s=20s_s(70-30)\\\\ \Delta Q_s=800s_s[/tex]
Heat energy gained by the liquid:
[tex]\Delta Q_l=ms_l\Delta T\\\\ \Delta Q_l=100s_l(30-20)\\\\ \Delta Q_l=1000s_l[/tex]
According to the conservation of energy:
[tex]\Delta Q_s=\Delta Q_l\\\\800s_s=1000s_l\\\\\frac{s_s}{s_l}=\frac{1000}{800}\\\\\frac{s_s}{s_l}=\frac{5}{4}[/tex]
Hence, the specific heat of the solid is more than that of the fluid
Learn more about specific heat:
https://brainly.com/question/2516072?referrer=searchResults
