Isaac purchased a house for $179,300,00. Every year, Isaac makes improvements so that the value of the house goes up by 4%.
Which of the following equations can be used to determine the number of years after purchase, that the value of Isaac's house will
be equal to 5197.230.002

Respuesta :

Answer:

The number of years in which house value goes up is 145 years .

Step-by-step explanation:

Given as :

The initial purchased value of the house = p = $179,300,00

The value of house goes up every years at the rate = r = 4%

Let The number of years in which house value goes up = t  years

The value of the house after t years = $A = $5197,230,002

Now, According to question

The value of the house after t years = The initial purchased value of the house × [tex](1+\dfrac{\textrm rate}{100})^{\textrm time}[/tex]

I.e A = $p × [tex](1+\dfrac{\textrm r}{100})^{\textrm t}[/tex]

Or,$5197,230,002 = $17930000 × [tex](1+\dfrac{\textrm 4}{100})^{\textrm t}[/tex]

Or, [tex]\dfrac{5197,230,002}{179,300,00}[/tex] = [tex](1+\dfrac{\textrm 4}{100})^{\textrm t}[/tex]

Or, 289.86 = [tex](1.04)^{t}[/tex]

Now, taking Log both side

So, [tex]Log_{10}[/tex]289.86 = [tex]Log_{10}[/tex] [tex](1.04)^{t}[/tex]

or, 2.462 = t ×  [tex]Log_{10}1.04

or, 2.462 = t × 0.01703

∴ t = [tex]\dfrac{2.462}{0.01703}[/tex]

I.e t = 144.56 ≈ 145

So, Number of years = t = 145 years

Hence The number of years in which house value goes up is 145 years . Answer

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