Answer:
Step-by-step explanation:
Given
There are 45 numbers out of which 5 numbers are required to win an enormous sum of money
No of ways in which 5 numbers can be selected out of 45 numbers.
[tex]^nC_r=\frac{n!}{(n-r)!r!}[/tex]
here n=45, r=5
[tex]^{45}C_5=\frac{45!}{40!5!}[/tex]
[tex]^{45}C_5=1221759[/tex]
out of which there is only combination foe contest winning
[tex]P=\frac{1}{1221759}[/tex]
When 100 different tickets are bought then
Probability of winning[tex]=\frac{100}{1221759}[/tex]
