Answer:
The length of Rectangle is (5 + 2 s) inches and width of rectangle is [tex]\dfrac{s^{2} }{5 + 2 s}[/tex] inches .
Step-by-step explanation:
Given as :
The length of the rectangle is 5 inches more than twice the length of the side of the square
The area of Rectangle = The area of square
Let the side of the square = s inches
So, The Area of square = side × side
I.e The Area of square = s × s = s² inches²
Again
Let The length of rectangle = L inches
And The width of rectangle = w inches
So, The Area of Rectangle = ( L × w ) inches²
So, According to question
The length of rectangle = 5 inches + twice length of square side
I.e L = ( 5 + 2 s ) inches
∵ Both The area same
So, L× w = s²
Or, w = [tex]\dfrac{s^{2} }{L}[/tex]
or, w = [tex]\dfrac{s^{2} }{5 + 2 s}[/tex] inches
So, The measure of length of Rectangle = L = (5 + 2 s) inches and width of rectangle = w = [tex]\dfrac{s^{2} }{5 + 2 s}[/tex] inches
Hence, The measure of length of Rectangle is (5 + 2 s) inches and width of rectangle is [tex]\dfrac{s^{2} }{5 + 2 s}[/tex] inches . Answer
