Answer:
The sound intensity is 16I
Explanation:
Given:
Dsitance d = 0.5
Amplitude = 2A
To Find:
sound intensity = ?
Solution:
We Know that
[tex]I \propto \frac{A^{2}}{r^{2}}[/tex]
When Distance is d, wuth amplitude A
The sound intensity [tex]I = C \frac{A^{2}}{d^{2}}[/tex]---------------------(1)
Where
C is proportionality constant
Substituting the values
[tex]I^'= C \frac{(2A)^{2}}{0.5^{2}}[/tex]
[tex]I^'= C \frac{4A^{2}}{0.25d^2}[/tex]
[tex]I^'= C \frac{16A^{2}}{d^2}[/tex]
[tex]I^'= \frac{16CA^{2}}{d^2}[/tex]
From 1 , [tex]I^'= 16I[/tex]
