Speed can be found through the application of concepts related to potential energy and kinetic energy, for which you have
[tex]KE = PE[/tex]
[tex]\frac{1}{2}mv^2 = mgh[/tex]
Where,
m = mass
v = Velocity
g = Gravitational acceleration
h = Height
Re-arrange to find the velocity we have,
[tex]v^2 = 2gh[/tex]
[tex]v = \sqrt{2gh}[/tex]
[tex]v = \sqrt{2(9.8)(0.54)}[/tex]
[tex]v = 3.253m/s[/tex]
Therefore the speed at which water squirts out of the hole is .3253m/s
