Answer:
t = 55 min ⇒ m = 1497.692 g
Explanation:
polyaramide fiber:
∴ L = 1 m
∴ d = 710 μm
∴ m = 0.059 g
∴ t = 0.13 s
mass flow:
∴ mf = 0.059 g / 0.13 s = (0.454 g/s)×(60s/min) = 27.23 g/min
If t = 55 min:
⇒ m = mf×t = (27.23 g/min)×(55 min) = 1497.692 g
Answer:
[tex]m_{fiber}=1497.7g[/tex]
Explanation:
Hello,
In this case, as both the diameter and the length of the fiber is the same for the second case, one applies a simple rule of three to compute the mass of fiber that can be spun in 55 min as shown below:
[tex]m_{fiber}=\frac{55min*0.059g}{0.13s*\frac{1min}{60s} }\\m_{fiber}=1497.7g[/tex]
Best regards.
