Answer:
1115622.69
Explanation:
The relation between standard Gibbs energy and equilibrium reaction is shown below as:
[tex]\Delta{G^0} =-RT \ln K[/tex]
R is Gas constant having value = 0.008314 kJ / K mol
Given temperature, T = 298 K
Given, [tex]\Delta {G^0}=-34.5\ kJ/mol[/tex]
So,
[tex]-34.5=-0.008314\times 298 \ln K[/tex]
[tex]\ln \left(K\right)=\frac{34.5}{2.477572}[/tex]
[tex]\left(K\right)=e^{\frac{34.5}{2.477572}}[/tex]
[tex]K=1115622.69[/tex]
Answer:
The equilibrium constant is 1.116x10⁶
Explanation:
Please look at the solution in the attached Word file
