Answer:
The empirical formula of Caproic acid is [tex]C_{3}H_{6}O_{1}[/tex]
Explanation:
Empirical formula : It is the simplest whole number ratio of atoms present in the compound.
For e.g the empirical formula for glucose [tex]C_{6}H_{12}O_{6}[/tex] is [tex]CH_{2}O[/tex]
Actual Caproic acid is Hexanoic acid [tex]C_{6}H_{12}O_{2}[/tex]
Formula Used :
[tex]Moles = \frac{given\ mass}{Molar\ mass}[/tex]
How to solve the problem:(See the attached Image)