Answer:
The equation of the circular wheel is [tex]x^2+(y-74)^2=(70)^2[/tex].
Step-by-step explanation:
Given :
Radius of Ferris wheel r = 70 feet.
The distance between the wheel and the ground = 4 feet.
Also, the rectangular coordinate system shown has its origin on the ground directly below the center of the wheel.
So the x coordinate of center of wheel must be 0 , and y coordinate = 70 + 4 = 74
Thus, Coordinates of center = (0,74)
The equation of circle is given by :-
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Now center (h,k) = (0,74) and r = 70 , we get
[tex]x^2+(y-74)^2=(70)^2[/tex]
Hence, the equation of the circular wheel is [tex]x^2+(y-74)^2=(70)^2[/tex].
