Respuesta :

Answer:

79·433 × [tex]10^{-12}[/tex] W/m²

Explanation:

Given intensity of sound in decibels is 19

Formula for intensity of sound in decibels is

[tex]I_{1}[/tex] = 10 × ㏒(I ÷ [tex]I_{0}[/tex])

where

[tex]I_{1}[/tex] is the intensity of sound measured in decibels

I is the intensity of sound measured in W/m²

[tex]I_{0}[/tex] is the intensity of the sound that is taken as standard and it's value is equal to [tex]10^{-12}[/tex] W/m²

By applying the formula

19 = 10 × ㏒(I ÷ [tex]I_{0}[/tex])

⇒ 1·9 = ㏒(I ÷ [tex]I_{0}[/tex])

⇒ antilog(1·9) = I ÷ [tex]I_{0}[/tex]

⇒ 79·433 = I ÷ [tex]10^{-12}[/tex]

⇒ I = 79·433 × [tex]10^{-12}[/tex] W/m²

∴ Intensity of sound = 79·433 × [tex]10^{-12}[/tex] W/m²

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