Answer:
1) P = 116.75 psi
2) V = 0.565 L.
3) V = 373.33 ml
Explanation:
1) Given, the pressure in tire is 105 psi at 25°C = 298 K
and then it is moved to another place where temperature is -5°C = 268 K.
Now, as the volume of tire remained constant, from gas law,
[tex]\frac{P}{T}[/tex] = constant.
⇒ P₁T₂ = P₂T₁ .
⇒ 105×298 = P ×268. ⇒ P = 116.75 psi .
2) Given, balloon with volume 0.55 L at 22°C = 295 K is placed outside where the temperature is 30°C = 303 K and also pressure is constant
⇒From gas laws, [tex]\frac{V}{T}[/tex] = constant
⇒ 0.55 × 303 = V × 295. ⇒ V = 0.565 L.
3) Given, pressure in balloon changes from 0.80 atm to 1.2 atm
and initial volume is 560 ml.
As the temperature remained constant, from gas laws,
PV = constant.
⇒ 0.80 × 560 = 1.2 × V. ⇒ V = 373.33 ml.
