Answer:
Step-by-step explanation:
Given that the percentage of physicians who are women is 27.9%. In a survey of physicians employed by a large university health system,
45 of 120 randomly selected physicians were women.
Sample size n = 120
Sample proportion p = [tex]\frac{45}{120} \\=0.375[/tex]
H0: p = 0.279
Ha: p >0.279
(Two tailed test at 5% significance level)
p difference = 0.096
STd error of p assuming H0 true
= [tex]\sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.279(0.721}{120} } \\=0.041[/tex]
Test statistic Z = [tex]\frac{0.096}{0.041} \\=2.345[/tex]
Z critical value one tailed is 1.645
Since Z statistic > 1.645 we reject H0
There is evidence to conclude that the proportion of women physicians at the university health system exceeds
27.9%
