Answer:
46.3 N , Left
46.3, Right
Explanation:
[tex]F_{Ax}[/tex] = horizontal component of force at upper hinge A
[tex]m[/tex] = mass of the door = 17 kg
[tex]d[/tex] = distance between two hinges = 1.8 m
[tex]w[/tex] = width of the door = 1 m
Using equilibrium of torque about B
[tex]F_{Ax} d = (mg) (\frac{w}{2} )\\F_{Ax} (1.8) = (17)(9.8) (\frac{1}{2} )\\F_{Ax} = 46.3 N[/tex]
Direction : Towards left
[tex]F_{Bx}[/tex] = horizontal component of force at lower hinge B
Using equilibrium of force along vertical direction
[tex]F_{Bx} = F_{Ax}\\F_{Bx} = 46.3 N[/tex]
Direction : Towards right
