Answer:
B. 3,4 Volt
Step-by-step explanation:
Here we need to use Ohm's Law, because we have electric current, voltage and resistances. This law state: [tex]V=IR[/tex]
So, first we need to calculate the total resistance to then find the voltage. The resistances can be placed in two ways: in parallel, in series.
The pair 4 and 8 ohms are parallel, so we solve:
[tex]R_{T}=\frac{1}{R_{1}}+\frac{1}{R_{2}}[/tex]
[tex]\frac{1}{R_{T}}=\frac{1}{4}+\frac{1}{8}=\frac{8+4}{32}=\frac{12}{32}=\frac{3}{8}[/tex]
Which is, [tex]R_{T}=frac{8}{3}[/tex]
Now, this total resistance of parallels ones is placed in series with the 3 ohm resistance, in this case we just sum, because they are in series:
[tex]R=3+\frac{8}{3}=\frac{9+8}{3}=\frac{17}{3}=5.67 ohm[/tex]
Now that we have the total resistance of the circuit, we use the Ohm's Law:
[tex]V=IR\\V=(0.6A)(5.67ohm)=3.4 Volt[/tex]
Therefore, the right answer is B.
