Answer:
2.480 is test statistic
Step-by-step explanation:
Given that the claim is most adults would ease all of their personal information online if they could.
[tex]H_0: p = 0.50\\H_a: p >0.50[/tex]
(right tailed test)
p difference = 0.05
Std error=
[tex]\sqrt{pq/n} =\sqrt{0.5*0.5/609}[/tex]
0.0202
p difference / std error
Test statistic = p difference / std error
= [tex]\frac{0.05}{0.0202} \\=2.480[/tex]
